Question

If 25 ml of 0.667 M solution is diluted to a final volume of 100 ml what is the concentration of the final solution?

Answer 1

`0.167M`

Explanation:

Initial given molarity and volumes are:

`M_i=0.667M`

`V_i=25 ml`

What would be the final molarity `M_f=?` when the final volume is `V_f=100 ml`?

since the number of mole does not change, we can write:

`M_ixxV_i=M_fxxV_f`

`M_f=(M_ixxV_i)/(V_f)=(0.667Mxx25cancel(ml))/(100cancel(ml))=0.167M`