# If 26.35332 grams of Ca is reacted, how many moles of Calcium Oxide are produced?

May 31, 2017

$0.6575180$ $\text{mol CaO}$

#### Explanation:

I'll assume it reacts with excess oxygen, and forms only calcium oxide. The chemical equation for this reaction is

$2 \text{Ca" (s) + "O"_2 (g) rarr 2"CaO} \left(s\right)$

First let's calculate the number of moles of $\text{Ca}$ that reacts, using its molar mass:

26.35332cancel("g Ca")((1"mol Ca")/(40.08cancel("g Ca"))) = color(red)(0.6575180 "mol Ca"

Now, let's use the stoichiometrically equivalent values (the coefficients) in the chemical equation to calculate the number of moles of $\text{CaO}$:

0.6575180 cancel("mol Ca")((2"mol CaO")/(2cancel("mol Ca"))) = color(blue)(0.6575180 "mol CaO"

Therefore, $0.6575180 \text{mol CaO}$ will form.

By the way, I've never seen $7$ significant figures used in a problem before, I like it:)