If (3^n-3)+(3^2)=18, what is the value n?

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Answer 1 · 2018-04-02T06:57:13

#n=5#

Given: #3^(n-3)+3^2=18#

#<=>3^(n-3)+9=18#

#rArr 3^(n - 3) = 18 -9# [Transpose the #9# to R.H.S]

#=>3^(n-3)=9#

#rArr 3^(n-3)=3^2#

#rArr n-3=2#

[Applying the law of indices : If #a^m = a^n# and #a != 0#, then #m = n#]

#:.n=2+3#

#=5#