If 35 ml of the original 0.500 M #K_2Cr__2O_7(aq)# solution was evaporated to dryness, what mass #KaCr_2O_7(s)# would remain in the evaporating dish?

1 Answer
Feb 26, 2017

Answer:

#"At least........."5.15*g#

Explanation:

Originally, you have a #35*mL# volume of #0.500*mol*L^-1# #K_2Cr_2O_7#.

This represents a molar quantity of #35*mLxx10^-3*L*mL^-1xx0.500*mol*L^-1=0.0175*mol# with respect to #"potassium dichromate."#

This molar quantity represents a mass of #0.0175*molxx294.18*g*mol^-1=5.15*g#.

Of course, the salt might be solvated by several water molecules. This would increase the mass.