If #3Sec theta = x and 2Tan theta = y #, then how #x# and #y# are related ?

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Answer 1 · 2017-12-01T07:40:13

#y^2/4-x^2/9=-1#

.

#3sectheta=x#

#2tantheta=y#

#sectheta=x/3#

#sec^2theta=x^2/9#

#tantheta=y/2#

#tan^2theta=y^2/4#

We have a trigonometry identity that says:

#tan^2theta+1=sec^2theta#

#y^2/4+1=x^2/9#

#y^2/4-x^2/9=-1#