If 42.5 mol of an ideal gas is at 8.77 atm and 439 K, what is the volume of the gas?

2 Answers
Feb 28, 2018

Well, is not PV=nRT?

Explanation:

And so ...V=(nRT)/P

=(42.5*molxx0.0821*(L*atm)/(K*mol)xx439*K)/(8.77*atm)

=??*L...I make this approx. 175*L...

Feb 28, 2018

The volume of the gas is 175 liters.

Explanation:

To solve this problem, we need to use the ideal gas law:

PV=nRT

P is pressure in atmospheres, V is volume in liters, n is moles, R is the universal gas constant, and T is the temperature in Kelvins.

Plug the known values into the equation and solve for the volume.

(8.77)(V)=(42.5)(0.08206)(439)

V=((42.5)(0.08206)(439))/(8.77)=175 liters