Question

If 45.0g of O2are mixed with 45.0g of H2and the mixture is ignited, what mass of water is produced?

Answer 1

Approx. `40*g` water..........

Explanation:

We address the stoichiometric equation...

`H_2(g) +1/2O_2(g) rarr H_2O(l)`

And so we interrogate the molar quantities of reach reagent...

`"Moles of dihydrogen"=(45.0*g)/(2.016*g*mol^-1)=22.3*mol`

`"Moles of dioxygen"=(45.0*g)/(32.0*g*mol^-1)=1.41*mol`

And thus CLEARLY, there is a stoichiometric excess of dihydrogen gas, and the dioxygen is the limiting reagent. We can get at MOST `2xx1.41*molxx18.01*g*mol^-1=??*g`