Question

If 45 mL of a 1.5 M AgNO3 is added to KCl how many grams of AgCl can be formed? __ AgNO3 + __ KCl
__ AgCl + __ KNO3

Answer 1

The mass of AgCl is 9.7 g.

The steps involved are:
1. Write the balanced equation.
2. Use conversion factors to convert volume of AgNO₃ → moles of AgNO₃ → moles of AgCl → mass of AgCl

Step 1

The balanced equation is

AgNO₃ + KCl → AgCl + KNO₃

Step 2

Mass of AgCl = 0.045 L AgNO₃ × `(1.5"mol AgNO₃")/(1"L AgNO₃") × (1"mol AgCl")/(1"mol AgNO₃") × (143.3"g AgCl")/(1"mol AgCl")` = 9.7 g AgCl (2 significant figures)

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