If 4sin^2x=1,find the value of 2+3cos^2x/1-2sin^2x?

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Answer 1 · 2018-02-25T04:26:28

Given #4sin^2x=1#

#=>sin^2x=1/4#

Now

#(2+3cos^2x)/(1-2sin^2x)#

#=(2+3-3sin^2x)/(1-2sin^2x)#

#=(5-3sin^2x)/(1-2sin^2x)#

#=(5-3*1/4)/(1-2*1/4)=17/2#