If #4x+4y=9# and #x^2-y^2=-6/16#, what is the value of #2x-2y#?

1 Answer
Deepak G.
Aug 9, 2016

#2x-2y=-1/3#

Explanation:

#4x+4y=9#
or
#4(x+y)=9#
or
#x+y=9/4#
#x^2-y^2=-6/16#
or
#x^2-y^2=-3/8#
or
#(x+y)(x-y)=-3/8#
By Putting #(x+y)=9/4# in the equation #(x+y)(x-y)=-3/8#
We get
#9(x-y)/4=-3/8#
or
#x-y=-3/8 times 4/9#
or
#x-y=-1/6#
or
#2x-2y=-2/6#
or
#2x-2y=-1/3#

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