Question

If 50 mL of oxygen gas is compressed from 20 atm of pressure to 40 atm of pressure, what is the new volume at constant temperature?

Answer 1

`25*mL.........`

Explanation:

`"Boyle's Law"` holds that the product `PV=k` at constant `T`.

Since the temperature is constant here, we solve for `k`, and gets..........

`P_1V_1=P_2V_2`; so `V_2=(P_1V_1)/(P_2)=(20*atmxx50*mL)/(40*atm)`

`=25*mL` as required.............