# If 832J of energy is required to raise the temperature of a sample of aluminum from 20.0°C to 97.0°C, what mass is the sample of aluminum? The specific heat of aluminum is 0.90 J/(g x degrees C)

You can use the expression $E = m . c . \theta$ where E is the amount of energy involved, m is the mass of substance in g, c is the specific heat of the substance in $\frac{J}{g {.}^{o} C}$ and $\theta$ is the temperature change in celcius..
Rearranging for m gives $m = \frac{E}{c . \theta}$
This is $\frac{832}{0.9 . 77}$ = 12 g.