If 832J of energy is required to raise the temperature of a sample of aluminum from 20.0°C to 97.0°C, what mass is the sample of aluminum? The specific heat of aluminum is 0.90 J/(g x degrees C)

1 Answer
Jul 19, 2016

It works out to be 12 g.


You can use the expression #E = m.c.theta# where E is the amount of energy involved, m is the mass of substance in g, c is the specific heat of the substance in #J/(g.^oC)# and #theta# is the temperature change in celcius..

Rearranging for m gives #m = E/(c.theta)#

This is # 832 / (0.9 . 77)# = 12 g.