If #a=12, b=9#, and #c=4#, what is #(b^2-2c^2)/(a+c-b)#?

1 Answer
Mar 30, 2018

Answer:

See a solution process below:

Explanation:

Substitute:

  • #color(red)(12)# for each occurrence of #color(red)(a)#
  • #color(blue)(9)# for each occurrence of #color(blue)(b)#
  • #color(green)(4)# for each occurrence of #color(green)(c)#

and then calculate the result:

#(color(blue)(b)^2 - 2color(green)(c)^2)/(color(red)(a) + color(green)(c) - color(blue)(b))# becomes:

#(color(blue)(9)^2 - (2 * color(green)(4)^2))/(color(red)(12) + color(green)(4) - color(blue)(9)) =>#

#(81 - (2 * 16))/(16 - color(blue)(9)) =>#

#(81 - 32)/7 =>#

#49/7 =>#

#7#