If a #12 kg# object is constantly accelerated from #0m/s# to #40 m/s# over 18 s, how much power musy be applied at #t=1 #?

1 Answer
Mar 4, 2018

#29.61 W#

Explanation:

Force acting on the mass is #F=ma=(m(v-u))/t=(12(40-0))/18=26.67N# (where, #v# is the final velocity and #u# is the initial velocity)

Now,at #t=1# displacement was #s=0+1/2 (40/18) 1^2=1.11m#

So,work done after #1s# is #Fs=26.67*1.11=29.61J#

So,power applied = work done per unit time =#29.61/1=29.61W#