If #A= <-2 ,1 ,3 ># and #B= <-1 ,2 ,8 >#, what is #A*B -||A|| ||B||#?

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If #A= <-2 ,1 ,3 ># and #B= <-1 ,2 ,8 >#, what is #A*B -||A|| ||B||#?

1 Answer

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Answer 1 · 2016-10-18T15:59:28

#A.B-∥A∥∥B∥=28-sqrt(14*69)= 28-sqrt966#

Explanation:

#A=(-2,1,3)# and #(-1,2,8)#
The dot product #A.B=2+2+24=28#
#∥A∥=sqrt(4+1+9)=sqrt14#
#∥B∥=sqrt(1+4+64)=sqrt69#
so the final result is
#A.B-∥A∥∥B∥=28-sqrt(14*69)= 28-sqrt966#

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If #A= <-2 ,1 ,3 ># and #B= <-1 ,2 ,8 >#, what is #A*B -||A|| ||B||#?

1 Answer

Explanation:

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