If a #2 kg# object is constantly accelerated from #0m/s# to #15 m/s# over # 12s#, how much power musy be applied at #t= 6 #?

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Answer 1 · 2017-09-10T11:17:02

The power is #=18.75W#

#a=(v-u)/t=(15-0)/12=15/12=1.25ms^-2#

The force is

#F=ma=2*1.25=2.5N#

The speed at #t=6s# is

#v=u+at=0+1.25*6=7.5ms^-1#

The power is

#P=Fv=2.5*7.5=18.75W#