Question

If a `2 kg` object is constantly accelerated from `0m/s` to `16 m/s` over 6 s, how much power musy be applied at `t=1`?

Answer 1

`16/3`Newtons

Explanation:

The second Newton's law says

`F=m*a` where `m` is the mass, `F` the power and `a` the acceleration.
As the acceleration is constant `=> a=(v_f -v_0)/t = 16 m/s / 6s = 8/3 m/s^2`
Then, the power applied is `F=2kg*8/3 m/s^2 = 16/3 N`.