If a #2 kg# object is constantly accelerated from #0m/s# to #16 m/s# over # 8 s#, how much power musy be applied at #t=3 #?

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Answer 1 · 2017-03-25T13:01:21

The power is #=24W#

The curve of #a(t)#, v/s #t# is a straight line, passing through the origin

#v(t)=(16-0)/(8)*t#

#v(t)=2t#

#v(3)=6ms^-1#

The acceleration is the derivative of the speed

#a(t)=v'(t)=2ms^-2#

Which is constant

#F=ma#

#F=2*2=4N#

The power is

#P=F*v#

#P=4*v(3)=4*6=24W#