If $a = 3, b = - 4$ $a=3, b=-4$ and $c = - 5$ $c=-5$ , what is $a b^{2} - a c$ $ab^2-ac$ ?

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Answer 1 · 2016-08-19T14:01:49

$= 63$ $=63$

$a b^{2} - a c$ $ab^2-ac$

$= a (b^{2} - c)$ $=a(b^2-c)$

$= 3 ({(- 4)}^{2} - (- 5))$ $=3((-4)^2-(-5))$

$= 3 (16 + 5)$ $=3(16+5)$

$= 3 \times 21$ $=3times21$

$= 63$ $=63$

If a=3,b=−4a=3, b=-4 and c=−5c=-5, what is ab2−acab^2-ac?