If #A = <4 ,2 ,5 >#, #B = <-8 ,3 ,6 ># and #C=A-B#, what is the angle between A and C?

1 Answer
Feb 10, 2016

1.04 radians

Explanation:

The angle between 2 vectors# ulacolor(black)(" and ") ulb# can be found using :

# costheta =( ula . ulb)/(|ula| |ulb|) #

where #thetacolor(black)(" is the angle between the vectors ")#

here C = A - B = (4,2,5) - (-8,3,6) = (12,-1,-1)

#ula . ulc = (4,2,5) . (12,-1,-1 ) = 48 - 2 - 5 = 41 #

# |ula| = sqrt(4^2+2^2+5^2) = sqrt45 #

and #|ulc| = sqrt(12^2+(-1)^2+(-1)^2) = sqrt146#

# rArr costheta = 41/(sqrt45 xx sqrt146#

and # theta = cos^-1 (41/(sqrt45 .sqrt146)) = 1.04color(black)(" radians ") #