If A = <4 ,2 ,5 >A=<4,2,5>, B = <-8 ,3 ,6 >B=<−8,3,6> and C=A-BC=A−B, what is the angle between A and C?
1 Answer
Feb 10, 2016
1.04 radians
Explanation:
The angle between 2 vectors
ulacolor(black)(" and ") ulb can be found using :
costheta =( ula . ulb)/(|ula| |ulb|) where
thetacolor(black)(" is the angle between the vectors ") here C = A - B = (4,2,5) - (-8,3,6) = (12,-1,-1)
ula . ulc = (4,2,5) . (12,-1,-1 ) = 48 - 2 - 5 = 41
|ula| = sqrt(4^2+2^2+5^2) = sqrt45 and
|ulc| = sqrt(12^2+(-1)^2+(-1)^2) = sqrt146
rArr costheta = 41/(sqrt45 xx sqrt146 and
theta = cos^-1 (41/(sqrt45 .sqrt146)) = 1.04color(black)(" radians ")