If #A = <4 ,2 ,5 >#, #B = <-8 ,3 ,6 ># and #C=A-B#, what is the angle between A and C?
1 Answer
Feb 10, 2016
1.04 radians
Explanation:
The angle between 2 vectors
# ulacolor(black)(" and ") ulb# can be found using :
# costheta =( ula . ulb)/(|ula| |ulb|) # where
#thetacolor(black)(" is the angle between the vectors ")# here C = A - B = (4,2,5) - (-8,3,6) = (12,-1,-1)
#ula . ulc = (4,2,5) . (12,-1,-1 ) = 48 - 2 - 5 = 41 #
# |ula| = sqrt(4^2+2^2+5^2) = sqrt45 # and
#|ulc| = sqrt(12^2+(-1)^2+(-1)^2) = sqrt146#
# rArr costheta = 41/(sqrt45 xx sqrt146# and
# theta = cos^-1 (41/(sqrt45 .sqrt146)) = 1.04color(black)(" radians ") #