If A = <4 ,-5 ,1 >, B = <5 ,1 ,-3 > and C=A-B, what is the angle between A and C?

1 Answer
Jun 20, 2016

Reqd. angle = arccos(30/sqrt2226).

Explanation:

A=<4,-5,1>, B=<5,1,-3>
:. C=A-B= <4-5,-5-1,1-(-3)> = <-1,-6,4>.

Let the reqd. angle be theta. Then, using dot product of A & C, we have,
A.C=||A||*||C|\costheta rArr <4,-5,1>.<-1,-6,4>=sqrt(4^2+(-5)^2+1^2)*sqrt((-1)^2+(-6)^2+4^2)*costheta

:.-4+30+4=sqrt42*sqrt53*costheta
:.30=sqrt2226*costheta
:. costheta=30/sqrt2226
:. theta = arccos(30/sqrt2226).