If A = <4 ,-5 ,-4 >, B = <-9 ,1 ,-6 > and C=A-B, what is the angle between A and C?

1 Answer
Feb 26, 2016

0.801 " radians" or 45.67^@

Explanation:

If A=< color(blue)(4, -5, -4) >
and B = < color(green)( -9, 1, -6) >
then
color(white)("XXX")C= A-B= < color(blue)4-(color(green)(-9)), color(blue)(-5)-color(green)(1), color(blue)(-4)-(color(green)(-6)) >

color(white)("XXXX")=< color(red)(13, -6, 2) >

theta_(AC) = arccos ((A*C)/(||A||xx||C||))

A*C= color(blue)(4)xxcolor(red)(13) +color(blue)((-5))xxcolor(red)((-6))+color(blue)((-4))xxcolor(red)(2)
color(white)("XXX")= 76

||A|| = sqrt(color(blue)(4)^2+color(blue)((-5))^2+color(blue)((-4))^2)
color(white)("XXX")=sqrt(57)

||C|| =sqrt(color(red)(13)^2+color(red)((-6))^2+color(red)(2)^2)
color(white)("XXX")=sqrt(209)

theta= arccos(76/(sqrt(57)*sqrt(209))) = arccos(4/sqrt(33))

color(white)("X")=0.801 " radians" or 45.67^@