Question

If a `5 kg` object is being constantly accelerated from `0m/s` to `12 m/s` over `6s`, how much power is being applied at `t= 1`?

Answer 1

Here,`power`= 20`W`

Explanation:

First,
`v`=12m/s
`u`=0m/s
`t`=6s

Therefore,`a=(v-u)/t`

`a=12/6=2m/s`

Since acceleration is constant=`2m/s`
now `v` at `t=2s`

#v=u+at=0+1x2=2#
                therefore #v=2#

`p=FXV`
`P=10X2=20W`