If a 5 kg object is being constantly accelerated from 0m/s to 12 m/s over  6s, how much power is being applied at t= 1 ?

Jan 25, 2016

Here,$p o w e r$= 20$W$

Explanation:

First,
$v$=12m/s
$u$=0m/s
$t$=6s

Therefore,$a = \frac{v - u}{t}$

$a = \frac{12}{6} = 2 \frac{m}{s}$

Since acceleration is constant=$2 \frac{m}{s}$
now $v$ at $t = 2 s$

$$v=u+at=0+1x2=2
therefore v=2


$p = F X V$
$P = 10 X 2 = 20 W$