If #A = <6 ,4 ,-7 >#, #B = <3 ,5 ,0 ># and #C=A-B#, what is the angle between A and C?
1 Answer
Mar 5, 2016
Explanation:
To calculate the angle between 2 vectors
#ula" and " ulc # use:
#costheta = (ula . ulc)/(|a||c|) # where
#theta" is the angle between the vectors "# now C = A - B = (6,4,-7)-(3,5,0) = (3,-1,-7)
so
#ula . ulc =(6,4,-7) . (3,-1,-7)#
#= (6xx3)+(4xx-1)+(-7xx-7) = 18-4+49 = 63#
#|ula| = sqrt(6^2+4^2+(-7)^2) = sqrt(36+16+49)=sqrt101#
#|ulc| = sqrt(3^2+(-1)^2+(-7)^2) =sqrt(9+1+49)=sqrt59#
#rArr theta = cos^-1(63/(sqrt101xxsqrt59)) ≈ 0.616" radians "#