If #A= <8 ,1 ,-4 ># and #B= <-2 ,4 ,3 >#, what is #A*B -||A|| ||B||#?

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If #A= <8 ,1 ,-4 ># and #B= <-2 ,4 ,3 >#, what is #A*B -||A|| ||B||#?

1 Answer

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Answer 1 · 2016-11-01T05:40:40

The answer is #=-24-9sqrt29#

Explanation:

The dot product #vecA.vecB=〈8,1,-4〉.〈-2,4,3〉=-16+4-12=-24#
Modulus of #vecA# #=∥〈8,1,-4〉∥=sqrt(64+1+16)=sqrt81=9#
Modulus of #vecB# #=∥〈-2,4,3〉∥=sqrt(4+16+9)=sqrt29#

And finally #vecA.vecB-∥vecA∥∥vecB∥=-24-9sqrt29#

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If #A= <8 ,1 ,-4 ># and #B= <-2 ,4 ,3 >#, what is #A*B -||A|| ||B||#?

1 Answer

Explanation:

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