We have,
#ul(sinA+sinB)+sinC=2sin((A+B)/2)cos((A-B)/2)+sinC....(star).#
But, #A+B+C=pi :. A+B=pi-C :. ((A+B)/2)=(pi-C)/2.#
#:. ((A+B)/2)=pi/2-C/2.#
# :. sin((A+B)/2)=sin(pi/2-C/2)=cos(C/2)....(star^1).#
Also, #sinC=2sin(C/2)cos(C/2).........(star^2).#
Utilising #(star^1) and (star^2)# in #(star),# we get,
# sinA+sinB+sinC,#
#=2cos(C/2)cos((A-B)/2)+2sin(C/2)cos(C/2),#
#=2cos(C/2){cos((A-B)/2)+sin(C/2)},#
#=2cos(C/2){cos((A-B)/2)+sin((pi-(A+B))/2)...[as, A+B+C=pi],#
#=2cos(C/2){cos((A-B)/2)+sin(pi/2-(A+B)/2)},#
#=2cos(C/2){cos((A-B)/2)+cos((A+B)/2)},#
#=2cos(C/2){2cos(((A-B)/2+(A+B)/2)/2)cos(((A-B)/2-(A+B)/2)/2),#
#=2cos(C/2){2cos(A/2)cos(-B/2)},#
#=4cos(A/2)cos(B/2)cos(C/2)....[because, cos(-x)=cosx].#
Hence, the Proof.
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