Question

'If a cricket ball of mass 150gm is moving with velocity 200m/s in air,a player catches the ball after 0.1 sec, then find the force exerted by the ball on his hand'???

Answer 1

`300 N`

Explanation:

`Given, Mass(m) = 150 gm = 150/1000 kg = 0.15kg`
Initial velocity (u) `= 200 m/s`
Final velocity(v) `= 0 m/s`
Time (t) `= 0.1 sec`
now, acceleration(a) `= (v-u)/t`
`-> (0-200)/0.1`
`-> -2000 m/s^2`
Force (f) = `m*a`
`-> 0.15*(-2000)`
`-> 300N`
therefore, the exerted force is 300 Newton
hope that helpful