# If a current of 1 A passing through a circuit generates 18 W of power, what is the resistance of the circuit?

$18 \setminus \Omega$

#### Explanation:

If $R \setminus \setminus \setminus \Omega$ is the electric resistance of the circuit carrying an electric current $I = 1 \setminus A$ then the power $P$ of the circuit is given as

$P = {I}^{2} R$

$R = \frac{P}{I} ^ 2$

$= \frac{18}{1} ^ 2$

$= 18$

hence the resistance of circuit is $18 \setminus \Omega$