If a current of #1 A# passing through a circuit generates #9 W# of power, what is the resistance of the circuit?

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Answer 1 · 2016-02-07T12:57:12

#9Omega#

We know that #P=IV#.

We also know that by ohm's law #V=IR#. We can put this #V# into the equation for power to obtain:

#P=I^2R#

Now rearrange to get #R# and we get:

#R = P/I^2#

Put your values of #I=1A# and #P=9W# into the equation and we get:

#R = 9/1^2=9Omega#