# If a current of 1 A passing through a circuit generates 9 W of power, what is the resistance of the circuit?

Feb 7, 2016

$9 \Omega$

#### Explanation:

We know that $P = I V$.

We also know that by ohm's law $V = I R$. We can put this $V$ into the equation for power to obtain:

$P = {I}^{2} R$

Now rearrange to get $R$ and we get:

$R = \frac{P}{I} ^ 2$

Put your values of $I = 1 A$ and $P = 9 W$ into the equation and we get:

$R = \frac{9}{1} ^ 2 = 9 \Omega$