If a current of 4 A passing through a circuit generates 625 W of power, what is the resistance of the circuit?

Mar 22, 2016

$R = 39 , 06 \text{ Ohm}$

Explanation:

$P : \text{Power}$
$R : \text{Resistance}$
$I : \text{Electric Current}$
$P = {I}^{2} \cdot R$

$R = \frac{P}{I} ^ 2$

$R = \frac{625}{4} ^ 2 = \frac{625}{16}$
$R = 39 , 06 \text{ Ohm}$