If a current of #4 A# passing through a circuit generates #64 W# of power, what is the resistance of the circuit?

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Answer 1 · 2018-03-07T06:59:50

The resistance is #=4Omega#

The current is #I=4A#

The power is #P=64W#

The power is

#P=UI#

and Ohm's Law is

#U=RI#

Therefore,

#P=UI=R*I*I=RI^2#

#R=P/I^2=64/4^2=4Omega#