# If a current of 5 A passing through a circuit generates 400 W of power, what is the resistance of the circuit?

Jun 22, 2018

The resistance is $= 16 \Omega$

#### Explanation:

The curent is $I = 5 A$

The power is $P = U I = 400 W$

Ohm's Law is $U = R I$

Therefore,

$P = U I = R {I}^{2}$

The resistance is

$R = \frac{P}{I} ^ 2 = \frac{400}{5} ^ 2 = 16 \Omega$