# If a gas at occupies 2.60 liters at a pressure of 1.00 atm, what will be its volume at a pressure of 3.50 atm?

Dec 3, 2016

Approx. $\frac{3}{4} \cdot L .$

#### Explanation:

$\text{Boyle's Law}$ gives us the relationship $P \propto \frac{1}{V}$ for constant $T$, and for constant amount of gas.

Thus $P V = k$. For constant temperature, and constant amount of gas, as pertains in this scenario, we write:

${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$

And thus V_2=(P_1V_1)/(P_2)=(2.60*Lxx1.00*atm)/(3.50*atm)=??L.

The best thing about using these simple experimental laws of proportionality is that we can persist with using intuitively easy units such as $\text{litres}$ and $\text{atmospheres}$. It is intuitively obvious that the volume of a gas sample under compression should reduce.