If a gas in a closed container is pressurized from 15.0 atm to 16.0 atm and its original temperature was 25°C, what would be the final temperature of the gas in Kelvin?
Gay-Lussac's Law deals with pressure and temperature.
If we rearrange and get
Since temperature needs to be in Kelvin for all gas law calculations,
That answer = 317.866666666666667