# If a gas is cooled from 323.0 K to 273.15 K and the volume is kept constant, what final pressure would result if the original pressure was 750.0 mmHg?

Dec 24, 2016

634 mmHg

#### Explanation:

From the Ideal Gas Laws we know that ${\left(\frac{P V}{T}\right)}_{1} = {\left(\frac{P V}{T}\right)}_{2}$ Inserting our given values into this equation with the correct temperature values we get:

(750 mmHg * V_1)/(323’K) = (P_2 * V_2)/(273.15’K) ; ${V}_{1} = {V}_{2}$

${P}_{2} = 750 \cdot \left(\frac{273.15}{323}\right)$

${P}_{2} = 634 m m H g$