# If a projectile is shot at a velocity of 28 m/s and an angle of pi/6, how far will the projectile travel before landing?

Feb 8, 2016

${x}_{m} = 69 , 204 m e t e r s$

#### Explanation:

$\theta = \frac{\pi}{6} \cdot \frac{180}{\pi} = {30}^{o}$
$\text{elapsed time: } {t}_{e} = \frac{2 \cdot {v}_{i} \cdot \sin 30}{g}$
${t}_{e} = \frac{2 \cdot 28 \cdot 0.5}{9 , 81}$
${t}_{e} = 2 , 854 s$
${x}_{m} = {v}_{i x} \cdot {t}_{e}$
${x}_{m} = {v}_{i} \cdot \cos 30 \cdot {t}_{e}$
${x}_{m} = 28 \cdot 0 , 866 \cdot 2 , 854$
${x}_{m} = 69 , 204 m e t e r s$