Question

If a projectile is shot at a velocity of `52 m/s` and an angle of `pi/3`, how far will the projectile travel before landing?

Answer 1

`x_(max)~=103,358m`

Explanation:

`"you can calculate by: "x_(max)=(v_i^2*sin^2 alpha)/(2*g)`
`v_i:"initial velocity"`
`alpha:" projectile angle"`
`g:"gravitational acceleration"`
`alpha=pi/3*180/pi=60^o`
`sin 60^o=0,866`
`sin^2 60^o=0,749956`
`x_(max)=(52^2*0,749956)/(2*9,81)`
`x_(max)~=103,358m`