# If a projectile is shot at a velocity of 6 m/s and an angle of pi/3, how far will the projectile travel before landing?

Horizontal Range =$\frac{{u}^{2} \sin \left(2 \alpha\right)}{g} = \frac{{6}^{2} \times \sin \left(2 \frac{\pi}{3}\right)}{9.8} = 3.18 m$