# If a projectile is shot at a velocity of 7 m/s and an angle of pi/4, how far will the projectile travel before landing?

Feb 20, 2016

1.25m

#### Explanation:

The range of a projectile is calculated as

$x = \frac{{v}^{2.} {\sin}^{2} \alpha}{2. g}$

$h e r e , V = 7 , \alpha = 45$ $g = 9.8 \frac{m}{s} ^ 2$

= $\frac{{7}^{2.} {\left(1 / \sqrt{2}\right)}^{2}}{2. 9.8}$

= $\frac{\left(\frac{49}{2}\right)}{19.6}$

=1.25m