# If a projectile is shot at a velocity of 8 m/s and an angle of pi/3, how far will the projectile travel before landing?

Dec 31, 2017

Range$= 3.2 \sqrt{3}$m

#### Explanation:

$v = 8 \frac{m}{s}$ and $\theta = \frac{\pi}{3}$

Range$= \frac{{v}^{2} \sin 2 \theta}{g}$

$g \cong 10 \frac{m}{s} ^ 2$(not mentioned in question)

Range$= \frac{64 \times \sin \left(\frac{2 \pi}{3}\right)}{10}$

Range = (64xxsqrt3)/(10xx2

Range$= 3.2 \sqrt{3}$m