# If a projectile is shot at a velocity of #9 m/s# and an angle of #pi/6#, how far will the projectile travel before landing?

##### 1 Answer

7.1m

#### Explanation:

Let the velocity of projection of the object be **u** with angle of projection

The vertical component of the velocity of projection is

Now if the time of flight be** T** then the object will return to the ground after T sec and during this T sec its total vertical dosplacement **h** will be zero. So applying the equation of motion under gravity we can write

The horizontal displacement during this T sec is

In our problem

So the distance travelled by the projectile before landing is