# If a rectangle measures 8 feet on the short side and 9.8 feet on the long side.What is the area of the rectangle in square feet?

Apr 20, 2018

$A = 78.4$ ${\text{ft}}^{2}$

#### Explanation:

Multiply the length and width of the rectangle to find its area:

$A = 9.8 \cdot 8$

$A = 78.4$ ${\text{ft}}^{2}$

Apr 20, 2018

If the decimal is giving you a problem consider this approach.

$78.4 \textcolor{w h i t e}{.} f {t}^{2}$

#### Explanation:

We have: $8 \text{ feet"xx9.8" feet}$

But 9.8 is the same as $98 \times \frac{1}{10}$

So re-write as:

$8 \times 98 \times \frac{1}{10} {\text{ ft}}^{2}$

$\textcolor{w h i t e}{\text{d}} \textcolor{w h i t e}{.} 9 \textcolor{w h i t e}{. .} 8$
ul(color(white)("d")color(white)(9999)8larr" Multiply")
$\underline{7 \textcolor{w h i t e}{.} 8 \textcolor{w h i t e}{. .} 4}$
$\textcolor{w h i t e}{\text{dd}} 6$

Now we multiply by $\frac{1}{10}$ to give:

$784 \textcolor{w h i t e}{.} f {t}^{2} \times \frac{1}{10} = 78.4 \textcolor{w h i t e}{.} f {t}^{2}$