# If a riding mower costs $300 more than a self-propelled mower and the combined cost of the two mowers is$1100, what is the cost of each mower?

Apr 24, 2018

The riding mower is $700 and the self-propelled mower is$400.

Because the riding mower is $300 more, the x in your equation will be the cost of the self-propelled mower. riding mower= x+300 self-propelled mower= x total cost= 1100 The equation is then built as the following based on the above. 1100=x+(x+300) There are no coefficients involved based on the given information that there are only two mowers. Then we solve: 1100=2x+300 1100-300=2+300-300 800=2x Divide both sides by 2 400=x So, the riding mower is$700 and the self-propelled mower is $400. Apr 24, 2018 The self-propelled mower costs $400, and the riding mower costs $700. #### Explanation: Let $x$equal the cost of the self-propelled mower, and (x+$300) equal the cost of the riding mower.

x+(x+$300)=$1100

Simplify.

2x+$300=$1100

Subtract $300 from both sides. 2x=$1100-300

2x=$800 Divide both sides by $2$. x=$400

x+$300=$400+$300=$700

The self-propelled mower costs $400, and the riding mower costs $700.