If a rocket with a mass of #3500 tons # vertically accelerates at a rate of # 1/2 m/s^2#, how much power will the rocket have to exert to maintain its acceleration at 7 seconds?

1 Answer
May 5, 2018

The power is #=126.18MW#

Explanation:

The mass of the rocket is #m=3500000kg#

The acceleration of the rocket is #a=1/2ms^-2#

The acceleration due to gravity is #=9.8ms^-2#

According to Newton's second Law, the net force on the rocket is

#F=m(a+g)=3500000*(9.8+1/2)=36050000N#

Assuming that the initial velocity of the rocket is #u=0ms^-1#

The velocity after #t=7s# is

#v=u+at=0+1/2*7=3.5ms^-1#

The power is

#P=Fv=36050000xx3.5=126.18MW#