If a rocket with a mass of 3500 tons vertically accelerates at a rate of # 1/5 m/s^2#, how much power will the rocket have to exert to maintain its acceleration at 9 seconds?

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Answer 1 · 2016-06-29T12:25:28

#63MW#

Given
#M->"Mass of rocket"=3500*10^3kg#
#a->"Acceleration"=1/5=0.2m/s^2#

#g->"Acceleration due to gravity"=9.8m/s^2#

#"Velocity after ts "(v)=at#

#"Force applied"(F)=M(g+a)#

#"Power at t s"#

#P(t)=Fxxv=M(g+a)at#

Power at 9 s

#P(9)=35xx10^5xx(9.8+0.2)xx0.2xx9W#
#= 63xx10^6 W=63"MW"#