If a rocket with a mass of #8000 " tons" # vertically accelerates at a rate of # 4 m/s^2#, how much power will the rocket have to exert to maintain its acceleration at 3 seconds?
1 Answer
May 7, 2018
Power is defined as the rate of doing work. As such Power
#P=vecFcdot vecv#
To maintain acceleration of rocket at a rate of
#F_uarr=m(a+g)#
Inserting given values we get
#F_uarr=8000xx1000(4+9.81)=1.1048xx10^8\ N#
Assuming rocket starts from rest and acceleration is constant, velocity after
#u=u+at#
#v_uarr=0+4xx3=12\ ms^-1#
We see that