# If a tire has a pressure of 11.9 Pa, a volume of 2.8 L at a temperature of 319 K, and the pressure increases to 13.4 kPa when the temperature rises to 325 K, what is the new volume of the tire?

Approx. $2.5 \cdot L$
We use the combined gas law, $\frac{{P}_{1} {V}_{1}}{T} _ 1 = \frac{{P}_{2} {V}_{2}}{T} _ 2$
Thus ${V}_{2} = \frac{{P}_{1} \cdot {T}_{2} \cdot {V}_{1}}{{P}_{2} \cdot {T}_{1}}$ $=$ $\frac{11.9 \cdot P a \times 325 \cdot K \times 2.8 \cdot L}{13.4 \cdot P a \times 319 \cdot K}$