Question

If a transformer consist of `770` turns in primary coil with `220` primary voltage produces `110` secondary voltage, then calculate the number of turns in secondary coil?

Answer 1

The number of turns is `=385`

Explanation:

The equation of the transformer is

`V_p/V_s=n_p/n_s`

The number of turns of the primary coil is `n_p=770 " turns"`

The number of turns of the secondary coil is `n_s= "? turns"`

The voltage in the primary coil is `V_p=220 " V"`

The voltage in the secondary coil is `V_s=110 " V"`

Therefore,

The number of turns of the secondary coil is

`n_s= V_s/V_p*n_p=110/220*770= 385 " turns"`

Answer 2

`385` turns in the secondary coil

Explanation:

Using the transformer equation,

`V_p/V_s=N_p/N_s`

• `V_p,V_s` are the voltages of the primary and secondary transformers

• `N_p,N_s` are the numbers of coil turns in the primary and secondary transfomers

And so, we got:

`(220color(red)cancelcolor(black)"V")/(110color(red)cancelcolor(black)"V")=(770 \ "turns")/(N_s)`

`N_s=(770 \ "turns")/2`

`=385 \ "turns"`