If a transformer consist of 770 turns in primary coil with 220 primary voltage produces 110 secondary voltage, then calculate the number of turns in secondary coil?

2 Answers
Apr 24, 2018

The number of turns is =385

Explanation:

The equation of the transformer is

V_p/V_s=n_p/n_s

The number of turns of the primary coil is n_p=770 " turns"

The number of turns of the secondary coil is n_s= "? turns"

The voltage in the primary coil is V_p=220 " V"

The voltage in the secondary coil is V_s=110 " V"

Therefore,

The number of turns of the secondary coil is

n_s= V_s/V_p*n_p=110/220*770= 385 " turns"

Apr 24, 2018

385 turns in the secondary coil

Explanation:

Using the transformer equation,

V_p/V_s=N_p/N_s

  • V_p,V_s are the voltages of the primary and secondary transformers

  • N_p,N_s are the numbers of coil turns in the primary and secondary transfomers

And so, we got:

(220color(red)cancelcolor(black)"V")/(110color(red)cancelcolor(black)"V")=(770 \ "turns")/(N_s)

N_s=(770 \ "turns")/2

=385 \ "turns"