If a transformer consist of #770# turns in primary coil with #220# primary voltage produces #110# secondary voltage, then calculate the number of turns in secondary coil?

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Nam D. Share
Apr 24, 2018

Answer:

#385# turns in the secondary coil

Explanation:

Using the transformer equation,

#V_p/V_s=N_p/N_s#

  • #V_p,V_s# are the voltages of the primary and secondary transformers

  • #N_p,N_s# are the numbers of coil turns in the primary and secondary transfomers

And so, we got:

#(220color(red)cancelcolor(black)"V")/(110color(red)cancelcolor(black)"V")=(770 \ "turns")/(N_s)#

#N_s=(770 \ "turns")/2#

#=385 \ "turns"#

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Apr 24, 2018

Answer:

The number of turns is #=385#

Explanation:

The equation of the transformer is

#V_p/V_s=n_p/n_s#

The number of turns of the primary coil is #n_p=770 " turns"#

The number of turns of the secondary coil is #n_s= "? turns"#

The voltage in the primary coil is #V_p=220 " V"#

The voltage in the secondary coil is #V_s=110 " V"#

Therefore,

The number of turns of the secondary coil is

#n_s= V_s/V_p*n_p=110/220*770= 385 " turns"#

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