If an engineer needs to design a helium tank with a capacity of 725 moles at STP, how big (volume) should it be?

At $S T P$ $1$ mole of Ideal gas occupies a volume of $22.4 \cdot {\mathrm{dm}}^{-} 3$
$22.4 \cdot {\mathrm{dm}}^{3} \cdot m o {l}^{-} 1 \times 725 \cdot m o l$ $=$ ??m^3
Remember that $1 L$ $=$ $1$ ${\mathrm{dm}}^{3}$ $=$ ${\left(1 \times {10}^{-} 1 \cdot m\right)}^{3}$ $=$ $\left(\frac{1}{10} ^ 3\right) {m}^{3}$