If arithmetic mean b/w two no is 64 and the geometric mean is 16 the harmonic mean b/w them is.....?

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Answer 1 · 2018-06-10T06:56:43

The harmonic mean is #=4#

Let the #2# numbers be #a# and #b#

Then,

The arithmetic mean is #AM=(a+b)/2#

The geometric mean is #GM=sqrt(ab)#

The harmonic mean is

#HM=2/(1/a+1/b)=(2ab)/(a+b)#

As,

#AM=64#

#GM=16#

#HM=(2*GM^2)/(2*AM)=2*16^2/(2*64)=4#